25+10t+t^2=0

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Solution for 25+10t+t^2=0 equation: 



25+10t+t^2=0

a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-10}{2}=-5$

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